Leetcode

844. Backspace String Compare

YGSEO 2020. 7. 21. 00:20
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다른 사람 솔루션

class Solution:
    def backspaceCompare(self, S: str, T: str) -> bool:
        
        ans = ''
        ans_2 = ''
        for i in S:
            if i == '#':
                ans = ans[:-1]
            else:
                ans += i
        
        for i in T:
            if i == '#':
                ans_2 = ans_2[:-1]
            else:
                ans_2 += i
        return ans == ans_2

list가 아닌 string을 활용해서 stack

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