Leetcode
844. Backspace String Compare
YGSEO
2020. 7. 21. 00:20
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다른 사람 솔루션
class Solution:
def backspaceCompare(self, S: str, T: str) -> bool:
ans = ''
ans_2 = ''
for i in S:
if i == '#':
ans = ans[:-1]
else:
ans += i
for i in T:
if i == '#':
ans_2 = ans_2[:-1]
else:
ans_2 += i
return ans == ans_2
list가 아닌 string을 활용해서 stack
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